对立事件
Complementary events
理解并运用所有互斥结果的概率之和为1这一规则；利用该规则求对立事件的概率（P(非A) = 1 − P(A)）。
Understand and apply the rule that probabilities of all mutually exclusive outcomes sum to one; use this to find the probability of a complementary event (P(not A) = 1 − P(A))
学习证据 / Evidence
- 验证转盘上列出的所有结果的概率之和等于1
- 计算掷骰子不掷出6的概率为1 − 1/6 = 5/6
- 识别概率分布中各项数值之和不等于1的错误
- Verify that probabilities of all outcomes listed for a spinner sum to 1
- Calculate the probability of NOT rolling a 6 as 1 − 1/6 = 5/6
- Identify an error in a probability distribution where the values do not sum to 1
评估问题 / Assessment
如果一个转盘有三个区域，其中一个区域的概率是0.4，另一个是0.35，{{name}}能否在没有人告知的情况下算出停在第3个区域的概率？
If a spinner has three sections and one has a probability of 0.4 and another has 0.35, can {{name}} work out the probability of landing on the third section without being told?